How To Escape $ Dollar Sign In Linux

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How To Escape $ Dollar Sign In Linux
Post Description: I Will Show You How You Can Escape The Dollar Sign $ In A Linux Shell Command
Tags: How, To, Escape, Dollar, Sign, In, Linux, quotes, programming, unix, escaping, single, quote, double
This Post Was Posted On Feb 02, 2010 By Webune Support #3101

How To Escape $ Dollar Sign In Linux by Webune Support

we provide linux dedicated servers - to help our customer who program in linux you might find this trick helpful

do you have a command that you use the dollar sign ($) and you want to display the actual $ dollar sign instead of the variable value, lets say for example you have this command where you want to find and replace values in a file

this is how our expenses.txt file looks like:
expenses.txt

Marry Jones: $455.22
Joe Smith: $255.00
John Maks: $655.55

ok, lets say we want to replace the value of Marry's salary from $455.22 to $500.00 we can use this command:

awk '{gsub(/\$455.22/, "$500.00", $0); print > FILENAME}' expenses.txt

that will change to:
expenses.txt

Marry Jones: $500.00
Joe Smith: $255.00
John Maks: $655.55

hope that helps

so basically if you want to escape the $ character in unix, just add the \ slash before or you might get a message the looks like this:

awk: warning: escape sequence `\$' treated as plain `$'

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edward

#3655 1

let me give you some examples, so you can see for yourself, try these commands and the what the output looks like:

echo $path

echo "$path"

echo '$path'

you will be surprise to know that when you use the single quotes, it doesnt display the value of $path variable, but instead, it prints the actual word $path

hope that helps. my name is edward, i am from the country of el salvador.

el salvador is a little country in central america. its quite and peaceful, yet it feels like paradise in the tropics. we have a computer club here. join us

Mar 29, 2010 Reply Report abuse

gander

#3546 2

i think you can space by like this options:

\$variable

'$variable'

"'$variable'"

$$variable

which one works?

Mar 02, 2010 Reply Report abuse